Matematika

Pertanyaan

tentukan n jika (n+2)!/(n+1)!=12 dan (n-1)!/(n-3)!=20

tolong di bantu yah!

1 Jawaban

  • (n+2)/(n+1)! = 12
    (n+2)(n+1)!/(n+1)! = 12
    n + 2 = 12
    n = 12 - 2 = 10
    (n-1)!/(n-3)! = 20
    (n-1)(n-2)(n-3)!/(n-3)! = 20
    n^2 - 3n + 2 = 20
    n^2 - 3n + 2 - 20 = 0
    n^2 - 3n - 18 = 0
    (n+3)(n-6) = 0
    n = -3 atau n = 6
    n = -3 tidak dipakai karena n ยป 0
    Jadi n = 6

Pertanyaan Lainnya