Matematika

Pertanyaan

tentukan penyelesaian dgn metode eliminasi
1. x-y+z = -2
x-y-z = 0
x+y+z = -6

1 Jawaban

  • x-y+z = -2 .......(1)
    x-y-z = 0 .......(2)
    x+y+z = -6 .......(3)

    eliminasi 1 dan 2
    x - y + z = -2
    x - y - z = 0
    ........................ –
    0x + 0y + 2z = -2
    2z = -2
    z = -2/2 = -1

    eliminasi 1 dan 3
    x - y + z = -2
    x + y + z = -6
    ........................ –
    0x - 2y + 0z = 4
    -2y = 4
    y = 4/-2 = -2

    eliminasi 2 dan 3
    x - y - z = 0
    x + y + z = -6
    ......................... –
    0x - 2y - 2z = 6
    -2y - 2z = 6
    -y - z = 3 .... (4)

    eliminasi 2 dan 4
    x - y - z = 0
    -y - z = 3
    ...................... –
    x + 0y + 0z = -3
    x = -3

    penyelesaian :
    X = -3
    Y = -2
    Z = -1

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