mohon bantuannya :) sebuah fungsi didefinisikan dengan rumus g(x) = 3x^2 - 16 a. hitunglah g(6) dan g(5) b jika nilai g(a) = 32 temtukan nilai a

g(x) = 3x^2 - 16
a. g(6) = 3 (6)^2 - 16
     = 3 x 36 - 16
   = 92
g(5) = 3 (5)^2 - 16
     = 3 x 25 - 16
   = 59
b. g(a) = 3a^2 - 16
   32 = 3a^2 - 16
  48 = 3a^2
  16 = a^2
a= 4 atau a= - 4

g(x) = [tex]3x^2[/tex] - 16

a. g(6) = 3([tex]6^2[/tex]) - 16 = 3 (36) - 16 = 108 - 16 = 92
g(5) = 3([tex]5^2[/tex]) - 16 = 3 (25) - 16 = 75 - 16 = 59

b. g(a) = [tex]3a^2[/tex] - 16
g(a) = 32, maka
32 = [tex]3a^2[/tex] - 16
32 + 16 = [tex]3a^2[/tex]
48 = [tex]3a^2[/tex]
[tex]a^2[/tex] = 48 : 3
[tex]a^2[/tex] = 16
a = [tex]\sqrt{16}[/tex]
a = 4