jika diketahui log 2=0,3010 dan log 3=0,4771 nilai 10912 adalah

LogAritMa

log 2 = 0,301
log 3 = 0,4771

log 12
= log (2² × 3)
= log 2² + log 3
= 2 log 2 + log 3
= 2 × 0,301 + 0,4771
= 0,602 + 0,4771
= 1,0791 ✔