Matematika

Pertanyaan

Integral x^2 - 2 per akar x dx

1 Jawaban

  • InTegraL

    ∫ax^n dx = a/(n+1) . x^(n+1) + C

    ••
    ∫(x² - 2/√x) dx
    = ∫(x² - 2x^-1/2) dx
    = x³/3 - 2x^1/2 /(1/2) + C
    = 1/3 x³ - 4√x + C

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