Matematika

Pertanyaan

No 25, sertakan caranya
No 25, sertakan caranya

2 Jawaban

  • Luas segitiga = 36V3
    (n/2)^2V3 = 36V3
    (n/2)^2 = 36
    n/2 = 6
    n = 12
    Jari-jari lingkaran luas segitiga,
    r = (abc)/(4L_{segitiga})
    r = (12^3)/(4 x 36V3)
    r = (12^3)/(12^2V3)
    r = 12/(V3)
    r = 4V3
    Sehingga panjang sisi persegi 8V3
    Selisih luas persegi dan lingkaran,
    = (8V3)^{2} - \pi(4V3)^2
    = (4V3)^2[2^2 - \pi]
    = 48(4 - \pi)
  • L ∆ = 36√3
    1/2 . s² sin 60° = 36√3
    s = 12 cm

    s² = r² + r² - 2r² cos 120°
    s² = 3r²
    r² = 48 cm²

    Selisih
    = 4r² - πr²
    = 48(4 - π) cm²
    Opsi C.