Sederhanakan bentuk aljabar tersebut!

a). [tex]\frac{4}{x+3}[/tex] - [tex]\frac{5}{x-1}[/tex] = [tex]\frac{4(x-1)}{(x+3)(x-1)}[/tex] - [tex]\frac{5(x+3)}{(x-1)(x+3)}[/tex] = [tex]\frac{4x-4}{x^2-x+3x-3}[/tex] - [tex]\frac{5x+15}{x^2-x+3x-3}[/tex] = [tex]\frac{4x-4-5x-15}{x^2+2x-3}[/tex] = [tex]\frac{-x-19}{x^2+2x-3}[/tex]


b). [tex]\frac{3}{2x+5}[/tex] + [tex]\frac{2}{6x^2+7x-20}[/tex] = [tex]\frac{3}{2x+5}[/tex] + [tex]\frac{2}{(2x+5)(3x-4)}[/tex] = [tex]\frac{3(3x-4)}{(2x+5)(3x-4)}[/tex] + [tex]\frac{2}{(2x+5)(3x-4)}[/tex] = [tex]\frac{9x-12}{(2x+5)(3x-4)}[/tex] + [tex]\frac{2}{(2x+5)(3x-4)}[/tex] = [tex]\frac{9x-12+2}{(2x+5)(3x-4)}[/tex] = [tex]\frac{9x-10}{(2x+5)(3x-4)}[/tex] = [tex]\frac{9x-10}{6x^2+7x-20}[/tex]

c). [tex]\frac{2a}{3x}[/tex] x [tex]\frac{2x-6xy}{12a}[/tex] = [tex]\frac{2a}{3x}[/tex] x [tex]\frac{2x(1-3y)}{12a}[/tex] = [tex]\frac{1-3y}{9}[/tex] = [tex]\frac{1}{9}[/tex] - [tex]\frac{3y}{9}[/tex] = [tex]\frac{1}{9}[/tex] - [tex]\frac{y}{3}[/tex]