Matematika

Pertanyaan

Mencari dx per dy dan d²y per d²x

X²+2y²-2xy+y=12

1 Jawaban

  • [tex]
    x^2+2y^2-2xy+y=12\\
    \Leftrightarrow \frac{d}{dy}\left(x^2+2y^2-2xy+y\right)=\frac{d}{dy}(12)\\
    \Leftrightarrow 2x\frac{dx}{dy}+4y\frac{dy}{dy}-2\frac{dx}{dy}\cdot y-\frac{dy}{dy}\cdot 2x+\frac{dy}{dy}=0\\
    \Leftrightarrow \frac{dx}{dy}\left(2x-2y\right)+4y-2x+1=0\\
    \Leftrightarrow \frac{dx}{dy}\left(2x-2y\right)=2x-4y-1\\
    \Leftrightarrow \frac{dx}{dy}=\frac{2x-4y-1}{2x-2y}
    [/tex]

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