Mencari dx per dy dan d²y per d²x X²+2y²-2xy+y=12
Matematika
Adityo1234
Pertanyaan
Mencari dx per dy dan d²y per d²x
X²+2y²-2xy+y=12
X²+2y²-2xy+y=12
1 Jawaban
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1. Jawaban supaat69
[tex]
x^2+2y^2-2xy+y=12\\
\Leftrightarrow \frac{d}{dy}\left(x^2+2y^2-2xy+y\right)=\frac{d}{dy}(12)\\
\Leftrightarrow 2x\frac{dx}{dy}+4y\frac{dy}{dy}-2\frac{dx}{dy}\cdot y-\frac{dy}{dy}\cdot 2x+\frac{dy}{dy}=0\\
\Leftrightarrow \frac{dx}{dy}\left(2x-2y\right)+4y-2x+1=0\\
\Leftrightarrow \frac{dx}{dy}\left(2x-2y\right)=2x-4y-1\\
\Leftrightarrow \frac{dx}{dy}=\frac{2x-4y-1}{2x-2y}
[/tex]