integral 2x (5x + 1) pangkat 6 dx adalah?

₁
∫ 5x (1-x)⁶ dx
⁰

dengan Tanzalin
5x    (1-x)⁶
5      -¹/₇ (1-x)⁷
0      -¹/₇ (-¹/₈) (1-x)⁸ = ¹/₅₆ (1-x)⁸


₁
∫ 5x (1-x)⁶ dx
⁰
= 5x · - ¹/₇ (1-x)⁷ - 5 · ¹/₅₆ (1-x)⁸

= [- ⁵/₇ x (1-x)⁷ - ⁵/₅₆ (1-x)⁸ ]₀¹

= - ⁵/₇ (1) (1-1)⁷ - ⁵/₅₆ (1-1)⁸ - (- ⁵/₇ (0) (1-0)⁷ - ⁵/₅₆ (1-0)⁸)

= 0 - 0 + 0 + ⁵/₅₆

= ⁵/₅₆  ← jawaban