butuh jawabannya boss :) tlong bantu.

3. f(x) = ⁴√2x^3 - 1
f(x) = (2x^3-1)^1/4
f'(x) = (2x^3-1)^1/4-1
= (2x^3-1)^-3/4
= -3/4(2x^3-1)^-3/4 . 6x²
= -3/4.6x²(2x^3-1)^-3/4
= -9/2x²(2x^3-1)^-3/4
= -9/2x² / (2x^3-1)^3/4
= -9/2x² / ⁴√(2x^3-1)³