koordinat salah satu puncak elips 4x²+9y²-48x+72y+144=0

jawab
ellips  (x -p)²/ a²  + (y- q)²/b² = 1
Puncak  ( p+_a , q)  atau ((p , q+_ b)

4x²-48x + 9y² +72y = - 144
4(x² -12x) + 9(y²+8y) = - 144
4 (x -6)² + 9(y + 4)² = - 144 + 4(6²) + 9(4²)
4(x -6)² + 9(y+4)² = 144
(x-6)²/36 + (y+4)²/16 = 1
p =  6, a= 6 , q = - 4 , b = 4
titik puncak
(p+- a, q) → (6+6, -4) atau (6-6, 4) → (12,4), (0, 4)
(p, q+-b ) → (6, -4+4) atau (6, -4 - 4) → (6,8) , (6, -8)