pada pemetaan f : x ax + b, jika f(3) = 10 & f(2) = -16, tentukan : * nilai a dan b * tentukan rumus fungsi * maka f(-4) tolong bantuannya ya please

f(x) = ax + b

f(3) = 3a + b = 10
f(2) = 2a + b = -16
_______________-
a = 26

3a + b = 10
3(26) + b = 10
78 + b = 10
b = 10 - 78
b = - 68

Rumus fungsi
f(x) = 26x - 68

f(-4) = 26(-4) - 68
= -104 -68
= -172

f(x) = ax + b

f(3) = 3a + b
10 = 3a + b

f(2) = 2a + b
-16 = 2a + b

Eliminasi
3a + b = 10
2a + b = -16
__________-
a = 26

Subtitusi
3a + b = 10
b = 10 - 3(26)
b = -68

f(x) = ax + b
f(x) = 26x - 68

f(-4) = 26(-4) - 68
f(-4) = -104 - 68
f(-4) = -172