diketahui luas selimut kerucut 550cm² dan jari jari alasnya 7 cm. hitunglah: a. Panjang garis pelukis kerucut b. Luas alas kerucut c. Volume kerucut

a. Luas selimut kerucut  = π.r.s
550 = 22/7.7.s
550 = 22.s
s = 550/22
s = 25 cm

b. Luas alas kerucut = Luas lingkaran
Luas alas kerucut = π.r²
Luas alas kerucut = 22/7.7.7
Luas alas kerucut = 22.7
Luas alas kerucut = 154 cm²

c. t = √s²-r²
t = √25²-7²
t = √625-49
t = √576
t = 24 cm

Volume kerucut = 1/3.π.r².t
Volume kerucut = 1/3.22/7.7.7.24
Volume kerucut = 1.22.7.8
Volume kerucut = 1232 cm³

pertama kita cari t nya dulu
t=lseimut/p×r
=550/7×22/7
=550×7/22×7
=550/22
=25cm
s =akar dari 25^2+7^2
=25,96
l alas =
=22/7×7×7
=22×7
154cm
v9lume =
1/3×22/7×7×7×25,96
1/3×154×25,96=
133261,333cm
jangan lupa difollowya ,semmembantu:)