Hasil dari 1.(x+3)pangkat 3 2.(x-5)pangkat 4 3.(x+1)pangkat 7 Dengan caranya.. Mohon bantuannya ya

jawab
(x+3)³  = 3c0 (x)³ + 3c1 (x)²(3) + 3c2 (x)(3)² + 3c3 (3)³
(x+3) = x³ + 9x² + 27x + 27

(x-5)⁴  = 4c0 (x)⁴ + 4c1 (x)³(-5) + 4c2 (x)²(-5)² + 4c3(x)(-5)³ + 4c4 (-5)⁴
= x⁴ - 20 x³ + 150x²  - 500 x + 625

(x+1)⁷ = 7c0 (x)⁷ + 7c1 (x)⁶(1) + 7c2 (x)⁵ (1)² + 7c3 (x)⁴(1)³ + 7c4 (x)³ (1)⁴
+ 7c5 (x)² (1)⁵ + 7c6 (x)¹(1)⁶ + 7c7 (1)⁷
= x⁷ + 7 x⁶ + 21 x⁵ + 35 x⁴ + 35 x³ + 21 x² + 7x + 1