bantu jawab ya no 23 dan 24

No. 23
∠ABC = ∠FCG = ∠CDE (sehadap)
3x-48 = x+22
      2x = 70
        x = 70/2
        x = 35
x+22 = 35+22 = 57°
∠ABC = ∠FCG = ∠CDE = 57°
∠BCF = 180° - 57° = 123° (A)

No. 24
∠BCA = 180° - 100° = 80°
∠CBA = 180° - 80° - 48° = 52°
2x-16 +52 = 180
      2x - 16 = 180 - 52
      2x - 16 = 128
              2x = 128 +16
              2x = 144
                x = 144/2
                x = 72° (D)