bantu jawab soal persamaan trigonometri

1.) √6 sin x - √2 cos x = -2
√6 sin x + √2 cos x = 2
dngan rumus :
k cos ( x - a)
dimana k = √a² + b²
Tan a = b/a
k = √(√6)²+(√2)²
= √6+2
=√8
Tan a = b/a
= √2 / √6
= 1/3√3
a = 30°
√6 sin x + √2 cos x = 2
k cos (x-a) = 2
√8 cos ( x -30) = 2
cos ( x-30) = 2/√8
(x-30) = 1/2√2 = cos 45°
(x1 - 30) = @ + k. 360
(x1 - 30) = 45 + k. 360
x1 = 45+30+k. 360
x1= 75 + k. 360
x1 = 75°

(x2-30) = -@ + k. 360
x2-30 = -45 + k. 360
x2 = -45+30+k. 360
x2 = -15 + k. 360
x2 = 345°

hp { 75°,345°}