fungsi G:R ---》R ditentukan oleh G(x) = ax^2+bx+c. jika G(3) = 3, G(1) = -+, dan G(0)=3, tentukan nilai a,b dan c. kemudian hitunglah G(52).. tolong dikerjakan

g(x) = ax² + bx + c
g(0) => 0 + 0 + c = 3
c = 3

g(3) => a(3)² + b(3) + 3 = 3
9a + 3b = 0 ( : 3)
3a + b = 0
b = -3a

g(1) =>a(1)² + b + 3 = -1
a + (-3a) = -4
-2a = -4
a = 2

b = -3a
b = -3(2)
b = -6

g(x) = 2x² - 6x + 3
g(52) = 2(52)² - 6(52) + 3
=>5099