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2Al + 3/2 O2 = Al2O3   delta H = -1669,8
C + 1/2 O2 = CO          delta H = -110,5


Al2O3 = 2Al + 3/2 O2 delta H = +1669,8
3C + 3/2 O2 = 3CO    delta H = -331,5 kJ
reaksi total: Al2O3 + 3C = 2Al + 3CO delta H = +1338,3 kJ

mol Al = g/Ar = 13,5/27 = 0,5 mol
kalor yang diperlukan = 1338 x 0,5 / 2 = +334,575 kJ