turunan (akar x+1)+3x pangkat 3 +2x+1

jawab
f(x) = √(x+1) + 3x³ + 2x + 1
f(x)= (x+1)^(1/2) + 3x³ + 2x + 1
turunan = f'(x) = 1/2 (x +1)^(-1/2) + 9x² + 2
f'(x) = 1/ 2√(x+1)  + 9x² + 2
f'(x)= √(x+1) / (2x+2)   + 9x² + 2
atau
f'(x)= [ √(x+1)+ 9x² (2x +2) + 2(2x+2)] / (2x+2)
f'(x) = [√(x+1) + 18x³ + 18x² + 4x + 4 ]/ (2x +2)