Limit mendekati 0 dari [tex] \lim_{x \to 0} \frac{tan^2 2x - sin^2 2x}{x^2 .sin^2 x} [/tex]
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Limit mendekati 0 dari [tex] \lim_{x \to 0} \frac{tan^2 2x - sin^2 2x}{x^2 .sin^2 x} [/tex]
1 Jawaban
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1. Jawaban Anonyme
jawab
limit (tan² 2x - sin² 2x ) / (x². sin² x)
x→ 0
limit ( sin² 2x/ cos² 2x ) - sin² 2x / (x² sin² x)
x→0
limit (sin² 2x - sin² 2x cos ² x) / (cos² 2x) (x². sin² x)
x→ 0
limit sin² 2x ( 1 - cos² 2x) / (cos² 2x )(x².sin² x)
x→ 0
limit sin² 2x ( sin² 2x) / (cos² 2x)(x² sin² x)
x → 0
limit ( sin⁴ 2x) / (cos² 2x )(x² sin² x)
x→ 0
= (1/cos² x) (2x)⁴/(x²)(x²)
= (1/cos 0) (16)
= 1/1 (16)
= 16