Xy^2=x-4 Ditanya=dy/dx

jawab

xy² = x - 4   →  xy² - x = -4 → x(y² -1)= - 4 → x= (-4)/(y² -1)
d(xy²) /dx = d(x -4)/dx
2xy y' = 1
y' = 1/ (2xy)
y' = 1/ (2y)(-4/(y²-1))
y' = (y²-1)/(-8y)