6x^2+8x-8=0 rumus kuadrat dan faktorisasi

6x² + 8x - 8 = 0
(6x - 4)(x+2) = 0
6x - 4 = 0
6x = 4
x = 4/6
x = 2/3

dan
x+2 = 0
x = -2


6x² + 8x - 8 = 0
a = 6
b = 8
c = -8
x₁ = (-b + √b²-4ac)/2a
x₁ = (-8 + √8²-4(6)(-8))/2(6)
x₁ = (-8 + √64+192)/12
x₁ = (-8 + √256)/12
x₁ = (-8 + 16)/12
x₁ = 8/12 = 2/3


x² = (-b - √b²-4ac)/2a
x² = (-8 - √8²-4(6)(-8))/2(6)
x² = (-8 - √64+192)/12
x² = (-8 - √256)/12
x² = (-8 - 16)/12
x² = -24/12 = - 2

Cara Lain :
6x² + 8x - 8 = 0
a = 6
b = 8
c = -8

6x² + 8x - 8 = 0
6x² + 8x = 8
x² + (b/a)x + (b/2a)² = (b/2a)² -c
x² + (8/6)x + (8/2(6))² = [8/(2(6))]² -(-8)
x² + (4/3)x + (8/12)² = (8/12)² +8
x² + (4/3)x + (2/3)² = (2/3)² +8
x² + (4/3)x + (2/3)² = (2/3)² +8
x² + (4/3)x + (2/3)² = 4/9 +8
x² + (4/3)x + (2/3)² = (32+64)/72
(x + 2/3)(x + 2/3) = 96/72
(x + 2/3)² = 4/3

Jadi,
x₁ + 2/3 = 4/3 
x₁ = 4/3 - 2/3
x₁ = (4-2)/3 
x₁ = 2/3
dan
x₂ + 2/3 = - 4/3 
x₂ = - 4/3 - 2/3
x₂ = (-4-2)/3 
x₂ = -6/3
x₂ = -2