Dik f(x)=3x²-6 dan g(x)=3x-19 tentukan (gof)¹ (x)

jawab

f(x) = 3x² -6
g(x)= 3x -19
gof(x) = g {f(x)} = g (3x² -6)
gof(x)= 3 (3x² -6)
1/3 y = 3x² -6
3x² = 1/3 y + 6
x² = 1/9 y + 2 = 1/9 (y+18)
x = √ 1/9 . √ (y+ 18) = 1/3 √(y+18)
gof⁻¹ (x) = 1/3 √(x+18)