tentukan persaman garis melalui titik (3,-5)dan (4,-3)

Materi PGL

Diketahui
x1 = 3; x2 = 4
y1 = -5; y2 = -3
Persamaan garis melalui dua titik yaitu (3, -5) dan (4, -3) adalah
[tex] \displaystyle \frac{y-y_1}{y_2 - y_1} = \frac{x-x_1}{x_2 - x_1} \\ \frac{y-(-5)}{-3-(-5)} = \frac{x - 3}{4 - 3} \\ \frac{y+5}{2} = x - 3 \\ y+5 = 2x-6 \\ 2x - y = 11 [/tex]

(x1,y1) = (3,-5)
(x2,y2) = (4,-3)

(y-y1) per (y2-y1) = (x-x1) per (x2-x1)
(y-(-5)) per (-3-(-5)) = (x-3) per (4-3)
y+5 per -3+5 = x-3 per 1
y+5 per 2 = x-3 per 1
y+5 kali 1 = x-3 kali 2
y+5 = 2x -6
5+6 = 2x-y
11 = 2x-y atau 2x-y = 11 atau 2x-y-11 = 0