Penyelesaian dari sistem persamaan -2y-4y+z=5 , x+2y-z=-4 , 3x+2y+z=0

-2x - 4y + z = 5..... pers 1
x + 2y - z = -4...... pers 2
3x + 2y + z = 0..... pers 3

#Eliminasi pers 1 & 2
-2x - 4y + z = 5
x + 2y - z = -4 +
____________
-x - 2y + 0 = 1.... pers 4

#Eliminasi pers 2 & 3
x + 2y - z = -4
3x + 2y + z = 0 +
____________
4x + 4y + 0 = -4.... pers 5

#Eliminasi pers 4 & 5
-x - 2y = 1 x2
4x + 4y = -4 x1
__________

sehingga mnjdi
-2x - 4y = 2
4x + 4y = -4 +
___________
2x + 0 = -2
2x = -2
x = -2/2
x = -1


#subsitusi x = -1 ke pers 4
= -x - 2y = 1
= -(-1) - 2y = 1
= 1 - 2y = 1
= -2y = 1-1
= y = 0/-2
= y = 0

#subsitusi x = -1 dan y = 0 kepers 1
= -2x - 4y + z = 5
= -2(-1) - 4(0) + z = 5
= 2 - 0 + z = 5
= z = 5
= z = 5-2
= z = 3/1
= z = 3

Sehingga dpt di temukan bahwa
x = -1
y = 0
z = 3