Diketahui ^2log 3 = x dan ^2log 10 = y. nilai ^6log 120 = ... tolong pakai cara yah terima kasih :)

jawab
²log3 = x
²log 10= y

⁶log 120 = ²log 120 /²log 6
= ²log (2². 3 . 10) / ²log (2.3)
= (²log 2² + ²log 3 + ²log 10) / (²log 2 + ²log 3)
= ( 2 + x + y) / (1 + x)