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Matematika
rickysinaga
Pertanyaan
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1 Jawaban
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1. Jawaban Anonyme
cos 2x - sin x - 1 = 0
(1 - 2 sin² x) - sin x - 1 = 0
2 sin² x + sin x = 0
sin x (2 sin x + 1) = 0
sin x = 0 ---> x = 0° , 180°
sin x = -1/2 ---> x = 210° , 330°
Interval : 0 < x < 360
HP = {180° , 210° , 330°}