16log32-9log81-1/25log125
Matematika
revandashyifa
Pertanyaan
16log32-9log81-1/25log125
1 Jawaban
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1. Jawaban Anonyme
LogAritMa
[16'log 32 - 9'log 81] - (1/25'log 125)
= [(2^4)'log 2^5 - (3^2)'log 3^4)] - 1/ (5^2)'log 5^3
= (5/4 - 4/2) - 1/ (3/2)
= -3/8 - 2/3
= (-9 - 8)/24
= -17/24