16'log 32 - 9'log 81 - (1 / 25'log 125)

Logaritma

^16 log 32 - ^9 log 81 - (1 / (^25 log 125))
= ^(2⁴) log 2^5 - (^9 log 9² ) - (^125 log 25)
= ( (5/4) x ²log 2) - (2 x ^9 log 9 ) - (^5³ log 5²)
= (5/4) - 2 - 2/3
= 15/12 - 6/12 - 8/12
= 1/12