F1= 5N,F2=3N,cos 60= 1/2 ,hitunglah resultan dan selisih vektornya
Fisika
aryamuhamad123
Pertanyaan
F1= 5N,F2=3N,cos 60= 1/2 ,hitunglah resultan dan selisih vektornya
1 Jawaban
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1. Jawaban SokYesLuAjg
R = akar F1² . F2² + 2.F1.F2 cos 60°
= akar 5² . 3² + 2.5.3 (1/2)
= akar 25 + 9 + 30 (1/2)
= akar 34 + 15
= akar 49 = 7N
selisih = akar F1²+ F2²- 2.F1.F2 Cos60
= akar 5² + 3² - 2.5.3 (1/2)
= akar 25 + 9 - 30 (1/2)
= akar 34 - 15
= akar 19
= 4,38 N
Semoga benar :)