Jika h'(x) = ax - 2 dengan h'(2) = 6 dan h(-1) = 4, integral h(x) dx =

Integral

h'(x) = ax - 2
h'(2) = 6

h'(2) = 2a - 2
2a - 2 = 6
2a = 8
a = 4

h'(x) = 4x - 2

Cari h(x) dlu dgn integralkan h'(x)

int 4x - 2 dx
= (4/2)x^(1+1) - 2x + C
= 2x² - 2x + C

h(-1) = 4

2 (-1)² - 2(-1) + C = 4
2.1 + 2 + C = 4
4 + C = 4
C = 0

h(x) = 2x² - 2x

int 2x² - 2x dx
= 2/(2+1) . x^(2+1) - 2/(1+1) . x^(1+1)
= [tex] \dfrac{2}{3} x^3 - x^2 [/tex]